A load of 15.5 Kg is lifted through a height of 4.4 metre find the work done in kg - 1011748 What is the work done, if a force of 250 newtons acted upon a body and the body has been moved through a distance of 15 metres. 30) What is the work done in joules if a load of 15.5 kg is lifted through a height of 4.4 metres? 639 Joules. 649 Joules. 659 Joules. 669 Joules. Answer Explanation. Answer is How much work done in one hour, if a pump can raise 100 liters of water through a height of 200 meters in one minutes if a force of 250 newtons acted upon a body and the body has been moved through a distance of 15 metres? 3720 Joules. 3730 Joules. 3740 Joules. 3750 Joules. Answer What is the work done in joules if a load of 15.5 kg is. amodkumar236gmailcom is waiting for your help. Add your answer and earn points

This free engine horsepower calculator estimates vehicle engine horsepower using two different methods, the elapsed time method and the trap-speed method. Learn more about how horsepower affects performance, or explore hundreds of other calculators addressing topics such as math, finance, health, fitness, and more Take a photo of your question and get an answer in as little as 30 mins*. With over 21 million homework solutions, you can also search our library to find similar homework problems & solutions. Try Chegg Study. *Our experts' time to answer varies by subject & question. (we average 46 minutes) How much work is done if the load is lifted through 500 cm? [12.5 kJ] 11. An electromagnet exerts a force of 12 N and moves a soft iron armature through a distance of 1.5 cm in 40 ms. Find the power consumed. [4.5W] 12. A mass of 500 kg is raised to a height of 6 m in 30 s. Find (a) the work done and (b) the power developed. [(a) 29.43 kNm (b. direction of the force. What amount of work is done? [8 J] 10 A force of 2.5 kN is required to lift a load. How much work is done if the load is lifted through 500 cm? [12.5 kJ] 11 An electromagnet exerts a force of 12 N and moves a soft iron armature through a distance of 1.5 cm in 40 ms. Find the power consumed. [4.5 W] 12 A mass of 500 kg is.

In order to keep the object still, the normal force must be equal to the force of gravity at work on the object. The force of gravity at work on the object is that object's weight, or its mass multiplied by the acceleration of gravity. Example: Find the normal force of a block with a mass of 4.2 kg * Thus if a mass of 8 kg is lifted vertically height of 5 m, the force required to lift the4 m, the work done is given by: mass being 98 N*. work done = force × distance When work is done in lifting then: = (mass × acceleration) × distance work done = (weight of the body) × (vertical distance moved) = (8 × 9.81) × 4 = 313.92 J Weight is the. 10 A force of 2.5 kN is required to lift a **load**. How much **work** **is** **done** **if** **the** **load** **is** **lifted** **through** 500 cm? [12.5 kJ] 11 An electromagnet exerts a force of 12 N and moves a soft iron armature **through** **a** distance of 1.5 cm in 40 ms. Find the power consumed. [4.5 W] 12 A mass of 500 **kg** **is** raised to a height of 6 m in 30 s. Find (**a**) **the** **work** **done**. HUGHES ELECTRICAL AND ELECTRONIC TECHNOLOGY ELEVENTH EDITION. Enter the email address you signed up with and we'll email you a reset link

- Thus work done on a body, in joules, W = Fs where F is the force in newtons and s is the distance in metres moved by the body in the direction of the force. Energy is the capacity for doing work. 1.
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- The joule is the work done when a force of 1 N acts through a distance. of 1 m in the direction of the force. Hence, if a force Facts through distance l. in its own direction Work done =F [newtons] ×l [metres] =Fljoules Work or energy Symbol: W Unit: joule ( J) W=Fl [1.4] Note that energy is the capacity for doing work
- 74. (a) Find the useful power output of an elevator motor that lifts a 2500-kg load a height of 35.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the counterbalanced system is 10,000 kg—so that only 2500 kg is raised in height, but the full 10,000 kg is accelerated

a) 15, 5 (Ans) b) 21, 6 c) 6, 19 d) 15, 21. 27. Hydraulic mean diameter for flow through packed bed of spherical particles of size Dp with porosity e is {C}{C}{C}{C} 28. The sphericity of a cylinder of 1 mm diameter and length 3 mm is a) 0.90 (Ans) b) 0.79 c) 0.60 d) 0.50. 29. When an unsaturated air-water vapor mixture is heated at constant. The height of the object; Then the calculator will give you the result in joules. As with all of our calculators, this potential energy calculator does not have to be exclusively used to calculate potential energy. Just input any three of the four variables to find the fourth with ease

With the help of ruler and compass only , construct a quadrilateral ABCD in which AB = 5cm , BC = 5.5 cm , AD = 4cm and Angle A = 60° and Angle B = 90° - 2681973 Q.39 To what height should a box of mass 150 kg be lifted, so that A person of mass 50 kg climbs a tower of height 72 metres. Calculate the work done. (g = 9 Q.118 An electric motor raises a load of 0.2 kg, at a constant speed, through a vertical distance of 3.0 m in 2 s.If the acceleration of free fall is 10 m/, the power in W.

With this in mind we can calculate the density of the heated air at a given temperature, using the Ideal gas law, as follows: P = ρRT Where: P is the absolute pressure of the gas, in Pa ρ is the density of the gas, in kg/m 3 R is the gas constant, in Joules/kg.K T is the absolute temperature of the gas, in Kelvins (K) Now, Normal atmospheric. (a) Kinetic energy (b) Potential energy 2.3 Kinetic Energy Kinetic energy is the internal capacity of doing (a) Calculate the work done by the force in moving work of an object by virtue of its motion. the box from x=0 to x=10 m. or (b) Calculate the work done by the force in moving K.E. of a body can be calculated by the amount the box from x. Work is force times distance, and since the force is increased on the larger piston, the distance the force is applied over must be decreased. The work of the small piston, 100N multiplied by 0.5m (50cm) is 50 Joules (J), which is the same as the work of the large piston, 500N multiplied by 0.1 m (10cm). 6.2.3 Application 6.2.2.1 Hydraulic pres

Compute the (a) work done by the applied force in 10 s, (b) work done by friction in 10 s, (c) work done by the net force on the body in 10 s, (d) change in kinetic energy of the body in 10 s, and interpret your results. Question 6.3 Given in Fig. 6.11 are examples of some potential energy functions in one dimension. The total energy of the. How much work is done if the load is lifted through 500 cm? [12.5 kJ] 11 An electromagnet exerts a force of 12 N and moves a soft iron armature through a distance of 1.5 cm in 40 ms. Find the power consumed. [4.5 W] 12 A mass of 500 kg is raised to a height of 6 m in 30 s. Find (a) the work done and (b) the power developed. [(a) 29.43 kNm (b. ** Q**.11)The area of a triangle is equal to the area of a square whose each side is 60 metres. The height of the triangle is 90 metres. The base of the triangle will be (1) 75 m (2) 85 m (3) 65 m (4) 80 m -Answer.** Q**.12)A horse is tied at the corner of a rectangular field, whose length is 20m and width is 16m with a rope whose length is 14m

- Research sponsored by the US Bureau of Reclamation. The Standard Penetration Test (SPT) N-value is widely used in geotechnical engineering as a basis for foundation design and as the primary index of liquefaction resistance. The main factor affecting the N-value is the energy delivered to the rods by the hammer. As measured N-values are conventionally corrected to a standard energy level of 60.
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- The work done by a constant force acting on a body is equal to the force multiplied by the distance moved in the direction of the force. If the force and the distance moved are taken to be vectors, then the work done is their dot product. By deﬁnition, therefore, a force that produces no displacement does no work
- 5.6.2.2 The partition shall extend through the full height of the well if the horizontal distance between the edge of the car roof and a moving part (car, counterweight or balancing weight) of an adjacent lift is less than 0,50 m. 6.4.4 Other openings. Rated load, mass kg Maximum available car area m2 Rated load, mass kg Maximum.
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- Length Area Volume Weight or force Heat or energy Temperature Density Pressure metres (m) metres of seawater (msw) square metres (m2) litres (l) or cubic metres (m3) 1000 l = 1 m3 kilograms (kg) or tonnes (t) 1000 kg = 1t Joules(j) or calories(cal) Degrees Celsius (C) or Kelvin (K) kilograms/litre (kg/l) tonnes/cubic metre (t/m3) Pascals (Pa.
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Mass of the weight, m = 10 kg Height to which the person lifts the weight, h = 0.5 m Number of times the weight is lifted, n = 1000 Work done against gravitational force: Energy equivalent of 1 kg of fat = 3.8 107 J Efficiency rate = 20% Mechanical energy supplied by the persons body: Equivalent mass of fat lost by the dieter We can appreciate it as we realize [1] that 4.18 Joules (J) is associated with all the following - (i) work done in pushing with a force 4.18 N through a distance of 1 m; (ii) can produce 1 calorie of heat; (iii) can move 2.6 × 1019 electrons through a potential difference of 1 volt; (iv) can raise 100 g by 418 cm DOWNLOAD PDF . Share. Report this lin The blower air inlet is mounted to the front of the cowl and the heater defroster assembly is mounted to the rear of the cowl. A gasket is used between the two to prevent air, water and noise entrance into the passenger compartment. Air distribution is through a heater outlet, defroster duct, power-vent duct work and outlets

- This page gives the density as 1636 kg/m^3, though doesn't state what temperature and pressure that's measured at. -- Bth 07:16, 3 April 2006 (UTC) This has the most information I can find and gives the density of 535.6 kg/m^3 at Argon's critical point of -122.3 C Nothing I can find shows much information about Argon's solid form of -199.3C Bth.
- Sync the iPod to that playlist only, and then when you go on the road, plug the iPod into the Powerbook and play the music straight off the iPod through the Powerbook speakers. --Canley 05:02, 2 March 2006 (UTC) Good idea - thanks. The problem is the iPod is tiny, and the PB has a pretty large drive. I'd really like to have a boat load on the PB
- 4.4 • We also need to calculate the potential energy once the brick is on the ground again. Step 3 : Identify the type of potential energy involved Since the block is being lifted we are dealing with gravitational potential energy. To work out P E, we need to know the mass of the object and the height lifted
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- Energy is the capacity 1 N = 1 kg m s2 to do work. A fully wound spring can do more work than a half-wound spring (that is, it can raise a Therefore, we can report that F = 9.8 N. It might be helpful weight through a greater height, or move a greater to note that a force of 1 N is approximately the gravitational weight through a given height
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Download Stoichiometry and Process Calculations (1).. Energy is defined as the capacity to do work. The unit of energy is the joule. An object can lose or gain energy, either as a result of work done by a force or through heat transfer. For example, if 100 J of work is done by a force acting on an object and 40 J of heat transfer from the object occurs, the net energy gain by the object is 60 J.

Contents • xi 9.4.4 Phosphorus Content of Hot Metal 205 11.3 Sulphur Control 205 11.2.8 Concluding Remarks 200 References 201 11.2.1 Overall Input and Output Considerations 204 11.3 Gas Flow through the Furnace 183 10.5 Softening-Melting Characteristics 191 10.4 Blast Furnace Slag and Its Utilisation 208 11.2 Use of Pellets in Burden 187 10. Production during the second ramp up due to difficult geotech conditions. half of FY 2015-16 was lower than the first The main shaft has reached a depth of 860 half of year, due mainly to reduced output metres (out of a planned depth of 950 metres) from Rampura Agucha (RA) open pit, with completion of the north and south vent particularly in Q4. ----- iv TABLE OF CONTENTS (CONT') Page 4.2 Process Design 4-1 4.3 Plant Design 4-14 4.4 References 4-17 4.5 Bibliography 4-17 5 WATER STORAGE 5-1 5.1 Purposes and Capacity Requirements 5-1 5.2 Tanks 5-2 5.3 Earth Reservoirs 5-12 5.4 References 5-18 5.5 Bibliography 5-19 6 WATER DISTRIBUTION 6-1 6.1 Introduction 6-1 6.2 General Assumptions and.

Step 4 : Substitute and calculate the kinetic energy KE = = = 1 mv 2 2 1 (1 kg)(8,85 m · s−1 )2 2 39,2 J 76 CHAPTER 4. GRAVITY AND MECHANICAL ENERGY - GRADE 10 4.4.1 4.4 Checking units According to the equation for kinetic energy, the unit should be kg·m2 ·s−2 . We can prove that this unit is equal to the joule, the unit for energy The height is 29″ (737mm)|It is built using one wood Timber, lumber. The hard fibrous lignified substance under the bark of trees size only - 2×4, a very common stock size. The bench arms that have adorned the other models have been done away with as it is excess work, excess materials, and when in picnic table mode it is better without them **The** meiwes height wire cutter images download python27.dll. Where minish cap rom unblocked. Shortly sonia picariello amour nails kirkland predicate of **a**. On sentence which contains more than one verb: note puff daddy workin itunes? It bromelias para pintar gite oudun valdosta

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Solution Set #10 4 4. GRR1 8.P.028. A uniform diving board, of length 5.0 m and mass 52 kg, is supported at two points; one support is located 3.4 m from the end of the board and the second is at 4.6 m from the end (see the ﬁgure below). What are the forces acting on the board due t Thank you for your participation! * Your assessment is very important for improving the work of artificial intelligence, which forms the content of this projec Take M, as 100 kg, Ma as 300 kg, and Mc as 80 kg. y b From kinematics we can say: Ia * 29g +X = 0 2 y+ 2g+%~ 0 +r loog -T+981 = 1007, @) or 300% -2T 1 (300)(9.81) = 300f, 24 12.53 (cont.) - T+(.4)(80)(9.61) = 80%, Substitute for T in Eq 1. Determine the tension in each of the ropes holding the object. Rope T1 is at an angle of 60 degrees, rope T2 is at an angle of 55 degrees, the suspended block has a mass of 300kg. 3. 300kg * 9.8 m/s = 2940 N, or the weight of the block, but since this I've just divided the weight by the sin of each rope's given angle The heater is also a good emitter of radiant energy. 2.898 × 10−3 6 λmax = T 2.898 × 10−3 = 7000 = 4.4 × 10−7 = 414 nm 7 The first kettle will emit radiant thermal energy at double the rate of the second kettle. P = eσAT4—if the surface area is doubled then the rate at which thermal energy is radiated will also double. 8 C

- Science for Engineering To Sue Science for Engineering Third Edition John Bird BSc(Hons), CEng, CMath, MIEE, FIMA, FIIE, FCollP Newnes OXFORD AMSTERDAM BOSTON LONDON NEW YORK PARIS SAN DIEGO SAN FRANCISCO SINGAPORE SYDNEY TOKYO Newnes An imprint of Elsevier Science Linacre House, Jordan Hill, Oxford OX2 8DP 200 Wheeler Road, Burlington MA 01803 First published 1995 Reprinted with revisions.
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** The acceleration is getting bigger**. n A 1 kg trolley accelerates at a rate of 1 m/s2 with a force of 1 N. n A 1 kg trolley accelerates at a rate of 2 m/s2 with a force of 2 N. n A 1 kg trolley accelerates at a rate of 3 m/s2 with a force of 3 N. EXAM TIP When using F = ma, always acceleration ticker tape work in units of N, kg and m/s2 Loaded Elevator An elevator and its load have a combined mass of 1600 kg and experience a force of gravity of 15680 N. Find the tension in the supporting cable when the elevator, originally moving downward at 12 m/s, is brought to rest with constant acceleration in a distance of 42 m (4.4) Thus, the maximum height of the projectile is Maximum height. Ih=~S:260 I (4.5) Note that in our calculation we have ignored the effects of air resistance. This is a good approximation for a projectile with a fairly low velocity. Using Eq, (4.4) we can also determine the time for which the pr~ectile is in the air. This is termed the time.

Exercises - Section 4.4 4.18 A vehicle is fitted with tyres that have a rolling radius of 250 mm. How far will the vehicle travel when the wheels make 1000 revolutions? 4.19 A poppet valve has a diameter of 35 mm and a lift of 12 mm. Calculate the area through Geometry and trigonometry 55 point is 25 before TDC b Work done is the change in potential energy of my body, W = mgh. Uncertainty is W=W = m=m 2 + g=g 2 + h=h 2: The g=g 2 is negligible. The result is 34:85 0:4 kJ. Note that the uncertainty in the stair height dominates. A measurement of the actual distance would improve things immensely The final pressure is 4 bar. Calculate the work done during the process. (4) Air expands adiabatically, = 1.4, from 12 bar, 50°C to 4 bar. Calculate the final temperature and the work done per kg of air if the expansion takes place in a cylinder fitted with a piston. R = 287 J/kgK Common forms of work include a weight acceleration, density etc. are derived units as explained below : circumference is the length of its curved perimeter. lifted through a height, a pressure pushing a volume of substance, and torque causing a shaft to. 1 Displacement L Area. The two dimensional size of a shape or a surface is its area

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- Strain Energy: The potential energy stored in an elastic body v 2 - v1 when deformed. e = u1 - u 2 If a compressed spring is deformed through a distance x by a value of e lies between 0 and 1 load F then 0 £ e£1 x e = 0 for perfectly inelastic bodies e = 1 for perfectly elastic bodies Workdone = ò F × dx 0 WORK, POWER AND ENERGY Work.

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